The following diagram shows a triangle with each of its sides produced both ways : What is the sum of degree measures of the angles numbered ?

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Q: 120 (CAPF/2009)
The following diagram shows a triangle with each of its sides produced both ways : What is the sum of degree measures of the angles numbered ?

question_subject: 

Maths

question_exam: 

CAPF

stats: 

0,7,10,7,8,2,0

keywords: 

{'angles': [0, 1, 1, 0], 'triangle': [0, 1, 0, 1], 'degree measures': [0, 0, 1, 0], 'following diagram': [0, 0, 1, 1], 'sum': [0, 2, 5, 4], 'sides': [3, 0, 3, 3]}

In the diagram, we can see that the triangle has three angles labeled A, B, and C.

Using the property that the sum of angles in a triangle is always 180 degrees, we can find the value of each angle.

Since angle A is opposite side B, it is equal to angle B, and since angle B is opposite side C, it is equal to angle C. Therefore, angles A, B, and C are all equal.

The sum of the degree measures of angles A, B, and C is given by:

A + B + C = A + A + A = 3A

To find the value of A, we can divide 720 degrees (option 1) by 3:

720 / 3 = 240

Therefore, each angle A, B, and C is equal to 240 degrees, and the sum of their degree measures is:

3A = 3 * 240 = 720 degrees.

Hence, option 1 (720 degrees) is the correct answer.

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