Mass of B is four times that of A, B moves with a velocity half that of A. Then B has :

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Q: 21 (NDA-I/2011)
Mass of B is four times that of A, B moves with a velocity half that of A. Then B has :

question_subject: 

Science

question_exam: 

NDA-I

stats: 

0,15,15,15,3,11,1

keywords: 

{'kinetic energy': [0, 0, 4, 7], 'velocity half': [0, 0, 0, 1], 'energy': [0, 0, 1, 2], 'mass': [0, 0, 2, 3], 'fourth': [1, 0, 6, 4]}

In this scenario, we have two objects, A and B, with a relationship between their masses and velocities. We are asked to determine the kinetic energy of B relative to A.

The kinetic energy of an object is given by the equation: KE = (1/2)mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.

Given that the mass of B is four times that of A and B moves with a velocity half that of A, we can calculate the kinetic energies of both objects.

Let`s assume the mass of A is m, and the velocity of A is v. Therefore, the mass of B will be 4m, and the velocity of B will be v/2.

Now, substituting the values into the kinetic energy equation, we can calculate the kinetic energy of A as (1/2)(m)(v^2) and the kinetic energy of B as (1/2)(4m)((v/2)^2).

Simplifying the expression for kinetic energy of B, we get (1/2)(4m)((v/2)^2) = (1/2)(4m)(v^2/4) = (1/

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