If the length of seconds pendulum is increased by 2%, how many seconds will it lose per day?

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Q: 7 (NDA-I/2008)
If the length of second’s pendulum is increased by 2%, how many seconds will it lose per day?

question_subject: 

Maths

question_exam: 

NDA-I

stats: 

0,1,14,5,6,3,1

keywords: 

{'length': [0, 0, 1, 0], 'many seconds': [0, 0, 1, 0]}

The correct answer is option 4: 864 s.

When the length of the second`s pendulum is increased by 2%, the time period of the pendulum will decrease. The time period is the time it takes for the pendulum to swing back and forth.

Given that the length is increased by 2%, we can calculate the new length by adding 2% of the original length to the original length.

Let`s assume that the original length of the pendulum is L. The new length will be L + (0.02 * L) = L + 0.02L = 1.02L.

Since the time period varies inversely with the square root of the length, the new time period can be calculated as follows:

New time period = Original time period * (Original length / New length)^(1/2)

= Original time period * (L / (1.02L))^(1/2)

= Original time period * (1 / 1.02)^(1/2)

= Original time period * (0.9803921569)

Now, we need to calculate the number of seconds lost per day. Since there are 24 hours in a day and 60 minutes in an

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