Statement I : Water (H2O) is more polar than Hydrogen Sulphide . Statement II: Oxygen is more electro-negative than Sulphur.

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Q: 4 (NDA-II/2011)

Statement I : Water (H2O) is more polar than Hydrogen Sulphide .
Statement II: Oxygen is more electro-negative than Sulphur.

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,8,11,8,4,5,2

keywords: 

{'hydrogen sulphide': [0, 0, 0, 1], 'sulphur': [0, 0, 0, 2], 'h2o': [0, 0, 2, 3], 'oxygen': [3, 0, 1, 0], 'water': [65, 15, 80, 129]}

Option 1 states that both Statement I and Statement II are true, and Statement II is the correct explanation of Statement I. Let`s evaluate each statement individually before analyzing their relationship.

Statement I: Water (H2O) is more polar than Hydrogen Sulphide.

Water (H2O) is a polar molecule because it has a bent shape and a highly electronegative oxygen atom, which results in an uneven distribution of charge. Hydrogen Sulphide (H2S) is also a polar molecule but less polar than water because of the lower electronegativity of sulfur compared to oxygen.

Statement II: Oxygen is more electronegative than Sulphur.

This statement is true. Electronegativity is a measure of an atom`s ability to attract electrons in a chemical bond. Oxygen has a higher electronegativity than sulfur, making oxygen more likely to pull the shared electrons towards itself.

Now, let`s consider the relationship between the two statements. Statement II provides a valid explanation for Statement I. The difference in electronegativity between oxygen and sulfur in water and hydrogen sulphide respectively is responsible for the difference in polarity between the two molecules. Therefore, Statement II is the correct explanation of Statement I.

In conclusion, Option

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