Two copper wires A and B of length I and 21 respectively, have the same area of cross-section. The ratio of the resistivity of wire A to the resistivi ty of wi re B is

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Q: 24 (NDA-II/2011)
Two copper wires A and B of length I and 21 respectively, have the same area of cross-section. The ratio of the resistivity of wire A to the resistivi ty of wi re B is

question_subject: 

Geography

question_exam: 

NDA-II

stats: 

0,4,13,2,3,4,8

keywords: 

{'resistivity': [0, 0, 0, 2], 'ratio': [1, 0, 1, 12], 'resistivi': [0, 0, 0, 1], 'length': [0, 0, 1, 0]}

In this question, we are given two copper wires, A and B, with different lengths but the same area of cross-section. We need to find the ratio of the resistivity of wire A to the resistivity of wire B.

The resistivity of a material is a characteristic property that determines how well it resists the flow of electric current. It is denoted by the symbol ρ (rho).

The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. The formula for resistance is R = ρ * (L/A), where R is the resistance, ρ is the resistivity, L is the length of the wire, and A is the cross-sectional area.

Given that the area of cross-section is the same for both wires, we can simplify the equation to R = ρ * L.

Since the resistance of a wire is directly proportional to its length, and wire A has a length of I and wire B has a length of 21, we can write the ratio of their resistances as R(A)/R(B) = I/21.

Now, we need to consider the ratio of their resistivities. Since the resistivity is not affected by the length or cross-sectional area, the ratio of

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