Potential at a point due to a point charge is V. The charge is doubled and also the distance of the point from the charge is doubled. The new potential is

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Q: 66 (NDA-II/2011)
Potential at a point due to a point charge is V. The charge is doubled and also the distance of the point from the charge is doubled. The new potential is

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,3,5,3,0,3,2

keywords: 

{'point charge': [0, 0, 0, 1], 'potential': [0, 0, 2, 1], 'new potential': [0, 0, 0, 1], '4v': [0, 0, 0, 1], '2v': [0, 0, 0, 1], 'charge': [1, 0, 4, 12], 'distance': [0, 3, 3, 3], 'point': [2, 1, 1, 1]}

In this question, we are given that the potential at a point due to a point charge is V. We need to find the new potential when the charge is doubled and the distance of the point from the charge is also doubled.

To solve this, let`s consider the expression for the potential due to a point charge:

V = k * (Q/r)

Here, V represents the potential, k is the electrostatic constant, Q is the charge, and r is the distance from the charge.

Now, when the charge is doubled and the distance is doubled, the new potential can be found using the same expression:

V` = k * (2Q)/(2r)

Simplifying this expression, we get:

V` = k * Q/r = V

Hence, the new potential is equal to the initial potential V. Therefore, the correct answer is option 3: V.

The potential at a point due to a point charge does not depend on the magnitude of the charge or the distance from the charge. It only depends on the electrostatic constant and the ratio of the charge to the distance.

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