. Which of the following statements is/are correct? 1. The major constituent mineral of granite rock is quartz. 2. The major constituent mineral of sandstone rock is feldspar. 3. The major constituent mineral of limestone rock is dolomite. Select the corr

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Q: 81 (NDA-II/2011)
.
Which of the following statements is/are correct?
1. The major constituent mineral of granite rock is quartz.
2. The major constituent mineral of sandstone rock is feldspar.
3. The major constituent mineral of limestone rock is dolomite.
Select the correct answer using the code given below :

question_subject: 

Geography

question_exam: 

NDA-II

stats: 

0,21,39,21,21,10,8

keywords: 

{'major constituent mineral': [0, 0, 0, 1], 'limestone rock': [0, 0, 0, 1], 'granite rock': [1, 0, 0, 1], 'sandstone rock': [0, 0, 0, 1], 'dolomite': [1, 0, 0, 0], 'quartz': [0, 0, 0, 1], 'feldspar': [0, 0, 0, 3]}

Option 1 states that the major constituent mineral of granite rock is quartz. This statement is incorrect. While quartz is a common mineral found in granite, it is not the major constituent. The major constituent mineral of granite is feldspar, specifically potassium feldspar and plagioclase feldspar. Therefore, option 1 is incorrect.

Option 2 states that the major constituent mineral of sandstone rock is feldspar. This statement is incorrect. The major constituent mineral of sandstone is quartz. Sandstone is primarily made up of grains of quartz cemented together by silica, calcium carbonate, or iron oxide. Therefore, option 2 is incorrect.

Option 3 states that the major constituent mineral of limestone rock is dolomite. This statement is incorrect. The major constituent mineral of limestone is calcite. Limestone is a sedimentary rock primarily made up of calcite. Dolomite, on the other hand, is a different mineral and can sometimes be found in limestone, but it is not the major constituent. Therefore, option 3 is incorrect.

As all the statements in options 1, 2, and 3 are incorrect, the correct answer should be "None of the above" or "Option 5."

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