The plot given above represents the velocity of a particle (in m/s) with time (in seconds). Assuming that the plot represents a semi-circle, distance traversed by the particle at the end of 7 seconds is approximately

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Q: 18 (NDA-II/2013)
The plot given above represents the velocity of a particle (in m/s) with time (in seconds). Assuming that the plot represents a semi-circle, distance traversed by the particle at the end of 7 seconds is approximately

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,0,2,0,0,1,1

keywords: 

{'velocity': [0, 2, 2, 6], 'distance': [0, 3, 3, 3], 'plot': [0, 0, 1, 4], 'particle': [0, 2, 8, 30], 'seconds': [3, 3, 8, 6]}

The given plot represents the velocity of a particle with time. To find the distance traversed by the particle, we need to first find the area under the velocity-time curve, which represents the displacement of the particle.

The plot is described as a semi-circle, meaning that the velocity starts at zero, increases to a maximum value, and then decreases back to zero. The area under the curve can be split into two parts - the first half of the semi-circle, where the velocity is increasing, and the second half, where the velocity is decreasing.

The formula to find the area under the curve is given by: Area = 1/2 * base * height.

For the first half of the semi-circle (from t=0 to t=7/2 seconds), the base is 7/2 seconds and the height is the maximum velocity. Since the maximum velocity is not given, we cannot calculate the exact area for the first half of the semi-circle.

For the second half of the semi-circle (from t=7/2 to t=7 seconds), the base is 7/2 seconds and the height is the same as the maximum velocity. Again, we do not have the maximum velocity, so we cannot calculate the exact area for the second half of

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