If three times of the first of the three consecutive odd integers is 3 more than twice the third, what is the third integer ?

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Q: 73 (CAPF/2014)
If three times of the first of the three consecutive odd integers is 3 more than twice the third, what is the third integer ?

question_subject: 

Maths

question_exam: 

CAPF

stats: 

0,11,11,11,6,2,3

keywords: 

{'consecutive odd integers': [0, 0, 0, 1], 'third integer': [0, 0, 0, 1]}

To solve this problem, let`s set up an equation using the given information. Let`s assume that the first odd integer is represented by x.

The second odd integer would then be x + 2 (since it is consecutive), and the third odd integer would be x + 4.

According to the given information, three times the first integer is equal to 3 more than twice the third integer. In equation form, this can be written as:

3x = 2(x + 4) + 3

Now, let`s simplify the equation:

3x = 2x + 8 + 3

3x = 2x + 11

Next, let`s isolate the x term:

3x - 2x = 11

x = 11

Therefore, the first odd integer is 11. And since the third odd integer is two more than the first integer, the third integer would be 11 + 4 = 15.

So, the correct answer is option 1: 15.

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