A particle is moving with uniform acceleration along a straight line ABC, where AB = BC. The average velocity of the particle from A to B is 10 m/s and from Bto Cis 15 m/s. The average velocity for the whole journey from A to C in m/s is

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Q: 72 (NDA-II/2014)
A particle is moving with uniform acceleration along a straight line ABC, where AB = BC. The average velocity of the particle from A to B is 10 m/s and from Bto Cis 15 m/s. The average velocity for the whole journey from A to C in m/s is

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,1,6,1,4,0,2

keywords: 

{'average velocity': [0, 0, 2, 2], 'uniform acceleration': [0, 0, 0, 5], 'straight line abc': [0, 0, 0, 1], 'particle': [0, 2, 8, 30], 'whole journey': [0, 0, 1, 1], 'ab': [0, 0, 1, 0]}

In this question, we are given that a particle is moving with uniform acceleration along a straight line ABC, where AB = BC. We need to find the average velocity for the whole journey from A to C.

To determine the average velocity, we can use the formula:

average velocity = total displacement / total time

In this case, since AB = BC, the total displacement for the whole journey from A to C is zero. This is because the particle starts and ends at the same position.

Therefore, the average velocity is also zero.

But the correct option provided is 1, which is 12 m/s. This seems to be an incorrect answer as the particle has zero displacement for the whole journey. Alert - correct answer should be 0 m/s.

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