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Q113 (CAPF/2026) Science & Technology › Basic Science (Physics, Chemistry, Biology)

If the relative density of gold is 19-3 and the density of water is 100 g/m3, what will be the density of gold in SI units?

Result
Your answer:  ·  Correct: B

Explanation

Relative density (also known as specific gravity) is the ratio of the density of a substance to the density of a reference substance, typically water at 4 °C. The formula is:

Relative Density = Density of substance / Density of water

To find the density of gold in SI units (kg/m3), we rearrange the formula:

Density of gold = Relative Density × Density of water

Given that the relative density of gold is 19.3 (noted as "19-3" in the question) and the standard density of water in SI units is 1000 kg/m3 (often written as 103 kg/m3, which appears as "100 g/m3" due to typographical errors), the calculation is:

Density of gold = 19.3 × 1000 kg/m3 = 19,300 kg/m3

Therefore, the density of gold is 19,300 kg/m3, which corresponds to option B.

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