A motorcycle has initial velocity of 5 m/s. After 3 seconds, the velocity is 7 m/s. The displacement of the motorcycle in 3 seconds is :

To find the displacement of the motorcycle, we use the kinematic equations for uniform acceleration. Given an initial velocity (u) of 5 m/s, a final velocity (v) of 7 m/s, and a time (t) of 3 seconds, we can calculate displacement (s) using the average velocity formula: s = [(u + v) / 2] × t. Substituting the values, we get s = [(5 + 7) / 2] × 3, which simplifies to (12 / 2) × 3 = 6 × 3 = 18 meters. Alternatively, one can first find the acceleration (a) using a = (v - u) / t, which is (7 - 5) / 3 = 2/3 m/s². Then, applying the formula s = ut + ½at², we get s = (5 × 3) + ½ × (2/3) × (3)² = 15 + 3 = 18 meters. Both methods confirm the displacement is 18 m.