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Q19 (CDS-I/2026) Science & Technology › Basic Science (Physics, Chemistry, Biology)

An object is launched horizontally from a height of 45 m above the ground with a speed of 10 m/s. The time at which the object will hit the ground is : (Take g = 10 m/s2)

Result
Your answer: —  Â·  Correct: C

Explanation

The problem involves projectile motion. When an object is launched horizontally, its vertical motion is independent of its horizontal velocity. The time taken to reach the ground depends only on the height and the acceleration due to gravity.

  • Initial vertical velocity (uy) = 0 m/s
  • Height (h) = 45 m
  • Acceleration due to gravity (g) = 10 m/s2

Using the second equation of motion for the vertical direction: h = uyt + ½gt2

Substituting the values: 45 = 0 + ½(10)(t2)
45 = 5t2
t2 = 9
t = 3 seconds

Therefore, the object will hit the ground in 3 seconds. The horizontal speed of 10 m/s affects the distance traveled horizontally (range) but does not change the time of fall.

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