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Q53
(CDS-II/2026)
Science & Technology › Basic Science (Physics, Chemistry, Biology)
A car of mass 800 kg is travelling at a speed of 40 km/h on a straight road. A force of 1000 N is applied on it in the direction of its velocity for 12 s. Which one among the following is the final speed of the car ?
Result
Your answer:
—
·
Correct:
C
Explanation
To find the final speed, we use Newton's Second Law of Motion and the first equation of motion.
- Step 1: Calculate Acceleration (a)
Given: Force (F) = 1000 N, Mass (m) = 800 kg.
Using F = ma, a = F/m = 1000/800 = 1.25 m/s2. - Step 2: Calculate Change in Velocity (Δv)
Given: Time (t) = 12 s.
Δv = a × t = 1.25 × 12 = 15 m/s. - Step 3: Convert Change in Velocity to km/h
To convert m/s to km/h, multiply by 18/5:
Δv = 15 × (18/5) = 3 × 18 = 54 km/h. - Step 4: Calculate Final Speed (v)
Initial speed (u) = 40 km/h.
v = u + Δv = 40 + 54 = 94 km/h.
Therefore, the final speed of the car is 94 km/h.
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