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Q9 (CISF/2020) Miscellaneous & General Knowledge › Important Days, Places & Events

Container I contains a mixture of 2 liters of oil and 3 liters of water. Container II contains a mixture of 6 liters of oil and 7 liters of water. 50% of the mixture of container I and 25% of the mixture of container II are transferred to container III. What is the proportion of oil and water in container III ?

Result
Your answer: —  Â·  Correct: D

Explanation

To determine the ratio of oil and water in Container III, we calculate the specific amounts transferred from each source:

  • From Container I: 50% of the mixture is moved.
    • Oil transferred = 50% of 2 liters = 1 liter
    • Water transferred = 50% of 3 liters = 1.5 liters
  • From Container II: 25% of the mixture is moved.
    • Oil transferred = 25% of 6 liters = 1.5 liters
    • Water transferred = 25% of 7 liters = 1.75 liters

Total quantities in Container III:

  • Total Oil = 1 + 1.5 = 2.5 liters
  • Total Water = 1.5 + 1.75 = 3.25 liters

The proportion of oil to water in Container III is 2.5 : 3.25. To simplify this ratio, we can multiply both terms by 100 to get 250 : 325. Dividing both by their greatest common divisor (25), we get 10 : 13.

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