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If the sum of a real number and its reciprocal is equal to 5, then what is the sum of the squares of the number and its reciprocal ?
Explanation
Let the real number be x. According to the problem, the sum of the number and its reciprocal is 5:
x + 1/x = 5
We need to find the sum of the squares of the number and its reciprocal, which is x2 + (1/x)2. To do this, we square both sides of the initial equation:
(x + 1/x)2 = 52
Applying the algebraic identity (a + b)2 = a2 + b2 + 2ab, we get:
x2 + (1/x)2 + 2(x)(1/x) = 25
x2 + 1/x2 + 2 = 25
Subtracting 2 from both sides of the equation:
x2 + 1/x2 = 25 - 2
x2 + 1/x2 = 23
Thus, the sum of the squares of the number and its reciprocal is 23.
SIMILAR QUESTIONS
If the difference of two numbers is 5 and their product is 10, then what is the value of the sum of squares of those numbers ?
If the sum of five consecutive even numbers is equal to the product of first five natural numbers, then which one of the following is the largest of those even numbers ?
When the square of the sum of two numbers are added to the square of their difference, we get 416. The difference between the square of the sum and square of the difference is 384. What are the numbers ?