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Q32
(CISF/2026)
Miscellaneous & General Knowledge › Important Days, Places & Events
Two brothers were born 3 years apart. After 10 years, the ratio of their ages will be 6 : 5. What will be the age of the younger brother after 15 years ?
Result
Your answer:
—
·
Correct:
B
Explanation
This is a problem based on linear equations. Let the current age of the younger brother be x years. Since the brothers were born 3 years apart, the older brother's current age is x + 3 years.
According to the question, after 10 years, the ratio of their ages will be 6:5. We can set up the following equation:
- Older brother's age after 10 years: (x + 3) + 10 = x + 13
- Younger brother's age after 10 years: x + 10
The ratio is: (x + 13) / (x + 10) = 6 / 5.
Cross-multiplying the terms: 5(x + 13) = 6(x + 10)
5x + 65 = 6x + 60
6x - 5x = 65 - 60
x = 5.
The current age of the younger brother is 5 years. Therefore, his age after 15 years will be 5 + 15 = 20 years.
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