The escape velocity of an object from the surface of the earth is 11.6 km/s. If the mass or the earth is increased four times, the resultant escape velocity would be

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Q: 28 (CDS-I/2002)
The escape velocity of an object from the surface of the earth is 11.6 km/s. If the mass or the earth is increased four times, the resultant escape velocity would be

question_subject: 

Geography

question_exam: 

CDS-I

stats: 

0,23,36,7,23,8,21

keywords: 

{'escape velocity': [0, 0, 1, 0], 'resultant escape velocity': [0, 0, 1, 0], 'earth': [0, 1, 1, 1], 'km': [0, 0, 2, 1], 'mass': [0, 0, 2, 3]}

The escape velocity of an object from the surface of the earth is the minimum velocity required for the object to escape the gravitational pull of the earth and not fall back. It depends on the mass of the earth and the distance from the center of the earth to the object`s starting point.

In this scenario, we are given that the escape velocity from the surface of the earth is 11.6 km/s. If the mass of the earth is increased four times, the resultant escape velocity would not change.

Option 2, which states that the escape velocity would still be 11.6 km/s, is the correct answer.

This is because the escape velocity is not directly proportional to the mass of the earth. Increasing the mass of the earth four times does not affect the escape velocity as long as the distance from the object to the center of the earth remains the same.

So, regardless of the change in the mass of the earth, the escape velocity from the surface remains constant at 11.6 km/s.