A jet plane flies through air with a velocity of 2 Mach. While the velocity of sound is 332 m/s the air speed of the plane is :

The Mach number is defined as the ratio of the true airspeed of an aircraft to the local speed of sound in the surrounding medium [t4][t5]. Mathematically, this is expressed as Mach Number = (Speed of Object) / (Speed of Sound). In this specific problem, the jet plane is flying at a velocity of 2 Mach, which signifies that its speed is exactly twice the speed of sound [t2]. Given that the velocity of sound is 332 m/s, the airspeed of the plane is calculated by multiplying the Mach number by the speed of sound: 2 × 332 m/s = 664 m/s [t2][t3]. This calculation confirms that the aircraft is traveling at a supersonic speed, exceeding the threshold of Mach 1 [t6]. Therefore, the correct airspeed of the jet plane is 664 m/s.