Left pan of a faulty balance weights 100 gram more than its right pan. A shopkeeper keeps the weight measure in the left pan while buying goods but keeps it in the right pan while selling his goods. He uses only 1 kg weight measure. If he sells his goods

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Q: 66 (IAS/2005)
Left pan of a faulty balance weights 100 gram more than its right pan. A shopkeeper keeps the weight measure in the left pan while buying goods but keeps it in the right pan while selling his goods. He uses only 1 kg weight measure. If he sells his goods at the listed cost price, what is his gain?

question_subject: 

Logic/Reasoning

question_exam: 

IAS

stats: 

0,3,13,3,6,4,3

keywords: 

{'weight measure': [0, 0, 1, 0], 'kg weight measure': [0, 0, 1, 0], 'right pan': [0, 0, 1, 0], 'left pan': [0, 0, 1, 0], 'gain': [0, 1, 2, 1], 'faulty balance': [0, 0, 1, 0], 'gram': [3, 0, 3, 2], 'goods': [0, 1, 5, 27], 'cost price': [0, 0, 1, 0], 'shopkeeper': [0, 0, 1, 0]}

The answer is calculated using the following approach: When the shopkeeper buys goods, he puts the weight in the left pan which is heavy by 100g. Hence, he buys 1100g of goods while paying for 1000g. When he sells, he puts the weight in the right pan, so due to the faulty balance, only 900g of goods are sold while the customer pays for 1000g. Therefore, for every 900g of goods sold, he gains 200g. To derive the percentage gain, we calculate: (gain/CP)*100. The gain here happens to be 200g and the cost price (CP) he paid is 900g. Hence, the profit percentage is (200/900)*100 = 200/9 % which is approximately 22.2%. However, the provided answer is 200/11% which is approximately 18.2%. Therefore, the alert should be:

Alert - correct answer should be option 4 - 200/9%.