To determine the number of aluminum ions present in 54 g of aluminum, we need to use the concept of molar mass and Avogadro`s number.

First, we calculate the number of moles of aluminum in 54 g by dividing the given mass by the molar mass of aluminum.

Molar mass of aluminum = 27 g/mol

Number of moles = Mass / Molar mass = 54 g / 27 g/mol = 2 moles

Since aluminum has a 1:1 ratio of aluminum ions, the number of aluminum ions is also 2 moles.

Next, we use Avogadro`s number to find the number of aluminum ions.

Avogadro`s number = 6.022 x 10^23 ions/mol

Number of aluminum ions = Number of moles x Avogadro`s number = 2 moles x 6.022 x 10^23 ions/mol

Simplifying, we get:

Number of aluminum ions = 1.2 x 10^24 ions

Therefore, the correct answer is option 4: 1.2 x 10^24.