An object of mass 5 kg is attached to the end of a rope. If the rope is pulled upward with an acceleration of 0.30 ms 2, what is the tension in the rope?

To find the tension in a rope pulling an object upward with acceleration, we apply Newton's second law. The net force is the difference between the upward tension (T) and the downward weight (mg), expressed as T - mg = ma [t5][t6]. Rearranging this formula gives T = m(g + a), where 'm' is the mass, 'g' is the acceleration due to gravity, and 'a' is the upward acceleration [t5][t8]. Given a mass (m) of 5 kg and an upward acceleration (a) of 0.30 m/s², and using the standard value for gravity (g = 9.8 m/s²) [c1][t6], the calculation is T = 5 * (9.8 + 0.30). This results in T = 5 * 10.1, which equals 50.5 N. Therefore, the tension required to accelerate the 5 kg mass upward at 0.30 m/s² is 50.5 N [t3][t4].

Sources

1. [1] Science ,Class VIII . NCERT(Revised ed 2025) > Chapter 5: Exploring Forces > Snapshots > p. 77