Question map
Not attempted Correct Incorrect ★ Bookmarked
Loading…
Q25 (NDA-II/2012) Science & Technology › Basic Science (Physics, Chemistry, Biology) › Basic mechanics concepts Answer Verified

One feels heavier in a lift when the lift

Result
Your answer: —  Â·  Correct: B
Explanation

The sensation of weight in a lift is determined by the normal reaction force (apparent weight) exerted by the floor. When a lift is stationary or moving steadily (constant velocity), the acceleration is zero, and the apparent weight equals the true weight (mg). However, when a lift just begins to go up, it undergoes upward acceleration. According to Newton's Second Law, the net force is F = N - mg = ma, leading to a normal force N = m(g + a). This increase in the normal force makes the person feel heavier. Conversely, moving down steadily results in no change in weight, and descending freely leads to weightlessness as the normal force becomes zero. Therefore, the feeling of being heavier occurs specifically during upward acceleration, which happens when the lift just begins its ascent.

How others answered
Each bar shows the % of students who chose that option. Green bar = correct answer, blue outline = your choice.
Community Performance
Out of everyone who attempted this question.
60%
got it right
✓ Thank you! We'll review this.

SIMILAR QUESTIONS

NDA-II · 2011 · Q44 Relevance score: 1.31

If the ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration ‘a’ is 3 : 2, then the value of‘a’ is

NDA-I · 2016 · Q58 Relevance score: 0.30

A man “weighing 70 kg is coming down in a lift. If the cable of the lift breaks suddenly, the weight of the man would become

CDS-I · 2007 · Q3 Relevance score: -0.24

Assertion (A) : An elevator is going up at constant velocity. If a person in the lift drops a coin in the elevator, then the coin will fall with uniform velocity. Reason (R) : The elevator is not moving with any acceleration or retardation.

CAPF · 2011 · Q49 Relevance score: -1.92

The acceleration due to gravity on the surface of the Earth is maximum and it

CDS-I · 2025 · Q24 Relevance score: -4.54

The minimum power required to lift a mass of 50 kg up to a vertical distance of 8 m in 10 s is : (Take g = 10 m/s2)