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For a particle revolving in a circular path, the acceleration of the particle is
Explanation
For a particle revolving in a circular path, the acceleration is primarily characterized by centripetal acceleration. Centripetal acceleration is defined as 'center-seeking' and is always directed inward toward the center of the circular path [t1][t3]. This acceleration acts in the radial direction, perpendicular to the tangential velocity [t3][t4]. While non-uniform circular motion may also involve tangential acceleration (along the tangent), the fundamental acceleration required for any circular motion to exist is centripetal acceleration [t1][t2]. Without this radial acceleration, the object would not maintain a circular path and would instead move in a straight line [t5]. Therefore, in the context of standard physics problems regarding the nature of circular motion acceleration, it is defined as being along the radius towards the center [t3][t9].
Sources
- [1] https://web.chem.ox.ac.uk/teaching/Physics%20for%20CHemists/Rotation/Circular.html
SIMILAR QUESTIONS
A particle is moving in a circular path of radius r at a constant speed v. Which one of the following graphs correctly represents its acceleration a?
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The position vector of a particle is given by r = 2t²î + 3tĵ + 4k̂. Then the instantaneous velocity v and acceleration a respectively lie:
- (A) on the xy-plane and along the z-direction
- (B) on the xz-plane and along the x-direction
- (C) on the yz-plane and along the x-direction
- (D) on the xy-plane and along the x-direction