Thermometer A and B have ice point marked at 15° and 25° and steam points a 75° and 125° respectively. When thermo-meter A measures the temperature of a bath as 60°, the reading of B for the same bath is

To find the reading on thermometer B, we use the principle of linear calibration between two temperature scales. The relationship is defined by the formula: (Reading - Ice Point) / (Steam Point - Ice Point) = Constant [t1][t2]. For thermometer A, the ice point is 15° and the steam point is 75°, giving a range of 60 units. When A reads 60°, its position on the scale is (60 - 15) / (75 - 15) = 45/60 = 3/4 [t3][t5]. For thermometer B, the ice point is 25° and the steam point is 125°, giving a range of 100 units. Applying the same proportion (3/4) to thermometer B: Reading B = 25 + (3/4 * 100) = 25 + 75 = 100° [t5]. Thus, when thermometer A measures 60°, thermometer B will read 100°.