In this question, we have three resistance coils connected in series, with resistance values of 1 ohm, 2 ohms, and 3 ohms. When resistance coils are connected in series, the total resistance is equal to the sum of the individual resistances. In this case, the total resistance is 1 + 2 + 3 = 6 ohms.
The potential drop across a resistor in a series circuit is directly proportional to its resistance. This means that the potential drop across the resistor with a resistance of 3 ohms will be greater than the potential drop across the resistors with lower resistances.
To find the potential drop across the resistance coil of 3 ohms, we can use Ohm`s Law. Ohm`s Law states that the potential difference (V) across a resistor is equal to the current (I) through the resistor multiplied by the resistance (R). In this case, the battery has a voltage of 9 volts and the total resistance is 6 ohms, so the current flowing through the circuit is 9V/6Ω = 1.5A.
The potential drop across the resistance coil of 3 ohms can now be calculated as 1.5A * 3Ω =