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Q107 (CDS-I/2004) Science & Technology › Basic Science (Physics, Chemistry, Biology) › Quantitative aptitude topics Answer Verified

Two men are standing on opposite ends of a bridge of 1200 metres long. If they walk towards each other at the rate of 5 m/minute and 10 m/ minute respectively, in how much time will they meet each other?

Result
Your answer: —  Â·  Correct: B
Explanation

The problem involves two objects moving towards each other from opposite ends of a 1200-metre bridge. According to the principles of relative speed, when two bodies move in opposite directions (towards each other), their relative speed is the sum of their individual speeds. In this case, the relative speed is 5 m/min + 10 m/min = 15 m/min. The time taken for them to meet is calculated by dividing the initial distance between them by their relative speed. Using the formula Time = Distance / Speed, we get Time = 1200 metres / 15 m/min = 80 minutes. This aligns with standard kinematic calculations where speed is defined as distance covered per unit time. Therefore, the two men will meet in exactly 80 minutes.

Sources

  1. [1] Science-Class VII . NCERT(Revised ed 2025) > Chapter 8: Measurement of Time and Motion > 8.3 Speed > p. 113
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