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Q74 (NDA-II/2008) Science & Technology › Basic Science (Physics, Chemistry, Biology) › Basic chemical principles Answer Verified

Which one of the following is an element which never exhibits positive oxidation state in any of its compounds?

Result
Your answer: —  Â·  Correct: C
Explanation

Fluorine is the most electronegative element in the periodic table. Due to its extreme electronegativity, it has a much stronger tendency to attract electrons than any other element it bonds with [t2][t4]. Consequently, in all its chemical compounds, fluorine always exhibits an oxidation state of -1 and never shows a positive oxidation state [t2][t6]. In contrast, other elements listed can exhibit positive states. Oxygen typically has an oxidation state of -2 but shows a positive state of +2 in compounds like oxygen difluoride (OF2) because fluorine is more electronegative [t2][t3]. Chlorine can exhibit multiple positive oxidation states, such as +1, +3, +5, and +7, when bonded to more electronegative atoms like oxygen or fluorine [t2][t3]. Carbon also exhibits a wide range of oxidation states from -4 to +4 depending on its bonding environment [t5][t7].

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