A wooden box of mass 2 kg and dimensions (30 cm x 15 cm x 10 cm) is placed on a table with sides 30 cm and 10 cm touching the tabletop. Which one of the following is the approximate pressure exerted on the table?

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Q: 49 (NDA-I/2022)
A wooden box of mass 2 kg and dimensions (30 cm x 15 cm x 10 cm) is placed on a table with sides 30 cm and 10 cm touching the tabletop.
Which one of the following is the approximate pressure exerted on the table?

question_subject: 

Maths

question_exam: 

NDA-I

stats: 

0,9,12,3,5,4,9

keywords: 

{'approximate pressure': [0, 0, 0, 1], 'table': [0, 0, 1, 0], 'mass': [0, 0, 2, 3], 'wooden box': [0, 0, 0, 1], 'tabletop': [0, 0, 0, 1], 'm2': [0, 1, 0, 6], 'kg': [0, 1, 9, 24], 'dimensions': [0, 1, 3, 1]}

The question asks about the approximate pressure exerted on the table by the wooden box. To calculate pressure, we need to divide the force exerted on an area.

The force exerted by the wooden box can be calculated using the formula F = m * g, where m is the mass of the box and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Here, the mass of the wooden box is given as 2 kg. So, the force exerted by the wooden box is F = 2 kg * 9.8 m/s^2 = 19.6 N.

To calculate the area of contact between the box and the table, we need to consider the dimensions of the box. The box is placed with sides of length 30 cm and 10 cm touching the tabletop. So, the area of contact is approximately 0.3 m * 0.1 m = 0.03 m^2.

Now, we can calculate the pressure using the formula P = F/A, where P is the pressure, F is the force, and A is the area of contact.

P = 19.6 N / 0.03 m^2 ≈ 653.3 N/m^

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