For an electric circuit given below, the correct combination of voltage (V) and current (I) is

In the given parallel circuit consisting of three resistors (100 Ω, 200 Ω, and 300 Ω), the voltage across each branch remains constant. Based on the circuit diagram from the NDA-II 2024 paper:

• Voltage (V): The current through the 100 Ω resistor is 3 A. Applying Ohm’s Law (V = I × R), the voltage across this resistor is 3 A × 100 Ω = 300 V. Since the resistors are in parallel, the total voltage (V) is 300 V.
• Total Current (I): The total current is the sum of the currents flowing through all parallel branches:
  • Current through 200 Ω resistor = 300 V / 200 Ω = 1.5 A.
  • Current through 300 Ω resistor = 300 V / 300 Ω = 1 A.
  • Total Current (I) = 3 A + 1.5 A + 1 A = 5.5 A.

Therefore, the correct combination is V = 300 V and I = 5.5 A, making Option B correct.