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Q11 (CDS-I/2017) Science & Technology › Basic Science (Physics, Chemistry, Biology) › Electricity and magnetism Answer Verified

A parallel-plate capacitor, with air in between the plates, has capacitance C. Now the space between the two plates of the capacitor is filled with a dielectric of dielectric constant 7. Then the value of the capacitance will become:

A) C
B) 7C
C) 8C
D) 14C

Result
Your answer: —  ·  Correct: B

Explanation

The capacitance (C) of a parallel-plate capacitor is determined by the formula: C = (ε₀ × A) / d, where ε₀ is the permittivity of free space, A is the plate area, and d is the distance between plates.

When a dielectric material with a dielectric constant (K) is inserted to fill the space between the plates, the capacitance increases by a factor of K. The new capacitance (C') is calculated as:

C' = K × C

Given that the dielectric constant K = 7, the new capacitance becomes 7 × C = 7C.

This increase occurs because the dielectric polarizes, reducing the net electric field and potential difference between the plates for a given charge, thereby increasing the device's ability to store charge.

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