When three resistors, each having resistance ry are connected in parallel, their resultant resistance is .x. If these three resistances are connected in series, the total resistance will be

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Q: 63 (NDA-II/2016)
When three resistors, each having resistance ry are connected in parallel, their resultant resistance is .x. If these three resistances are connected in series, the total resistance will be

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,3,8,6,2,3,0

keywords: 

{'resultant resistance': [0, 0, 0, 2], 'total resistance': [0, 0, 0, 3], 'resistances': [0, 0, 0, 3], 'resistance': [0, 0, 1, 2], 'resistors': [0, 0, 0, 1], 'parallel': [0, 1, 3, 5], '3x': [0, 0, 0, 1], '3rx': [0, 0, 0, 1], 'ix': [0, 0, 1, 2], 'series': [0, 1, 1, 0]}

When resistors are connected in parallel, their resultant resistance can be calculated using the formula: 1/R = 1/R1 + 1/R2 + 1/R3, where R1, R2, and R3 are the resistances of the individual resistors. In this case, when three resistors with resistance "ry" are connected in parallel, their resultant resistance is "x".

Therefore, using the formula for parallel resistances, we can write: 1/x = 1/ry + 1/ry + 1/ry. Simplifying this equation, we get: 1/x = 3/ry.

Now, to find the total resistance when these three resistors are connected in series, we add the resistances together because resistors in series add up: Rtotal = R1 + R2 + R3. In this case, the resistances are all "ry".

So, Rtotal = ry + ry + ry = 3ry.

Hence, the correct answer is option 2: 3ry, where ry represents the resistance of each individual resistor.