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Q61 (CAPF/2026) Miscellaneous & General Knowledge › Important Days, Places & Events

A large pot X contains 3 litres mixture consisting of milk and water in the ratio 3 : 2. Another pot Y contains 100 litres mixture consisting of milk and water in the ratio 9 : 1. How many litres of mixture from pot Y are to be poured into pot X to get a mixture with the ratio of milk to water as 17 : 3 in pot X?

Result
Your answer: —  ·  Correct: C

Explanation

To solve this, we first calculate the quantities of milk and water in pot X:

  • Total volume = 3 litres, Ratio = 3:2
  • Milk = 3 × (3/5) = 1.8 litres
  • Water = 3 × (2/5) = 1.2 litres

Let k be the number of litres poured from pot Y (Ratio 9:1):

  • Milk added = k × (9/10) = 0.9k
  • Water added = k × (1/10) = 0.1k

The new ratio in pot X must be 17:3:

(1.8 + 0.9k) / (1.2 + 0.1k) = 17 / 3

Cross-multiplying gives:
3(1.8 + 0.9k) = 17(1.2 + 0.1k)
5.4 + 2.7k = 20.4 + 1.7k
2.7k - 1.7k = 20.4 - 5.4
1.0k = 15
k = 15

Thus, 15 litres of the mixture from pot Y must be poured into pot X.

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