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Two metallic wires made from copper have the same length, but the radius of wire 1 is half that of wire 2. The resistance of wire 1 is R. If both the wires are joined together in series, the total resistance becomes:
- (A) 2R
- (B) 1.25R
- (C) 0.5R
- (D) 1.33R
Explanation
The resistance of a metallic conductor is directly proportional to its length and inversely proportional to its cross-sectional area [4]. Since both copper wires have the same length and material, their resistance depends solely on the area (A = πr²). Wire 1 has a radius half that of wire 2 (r1 = 0.5r2), meaning its area is one-fourth that of wire 2 (A1 = A2/4). Consequently, the resistance of wire 1 (R) is four times the resistance of wire 2 (R2), so R2 = R/4. When resistors are connected in series, the total resistance is the sum of individual resistances [4]. Therefore, the total resistance is R + R/4, which equals 1.25R or 5R/4. Option 2 is selected as the placeholder for this calculated value.
Sources
- [2] Science , class X (NCERT 2025 ed.) > Chapter 11: Electricity > Solution > p. 184
- [4] Science , class X (NCERT 2025 ed.) > Chapter 11: Electricity > 11.6 RESISTANCE OF A SYSTEM OF RESISTORS > p. 181
- [3] Science , class X (NCERT 2025 ed.) > Chapter 11: Electricity > What you have learnt > p. 192
SIMILAR QUESTIONS
Two wires are made having same length I and area of cross-section A. Wire 1 is made of copper and wire 2 is made of aluminium. It is given that the electrical conductivity of copper is more than that of aluminium. In this context, which one of the following statements is correct?
Two metallic wires A and B are made using copper. The radius of wire A is r while its length is l. A dc voltage V is applied across the wire A, causing power dissipation, P. The radius of wire B is 2r and its length is 2l and the same dc voltage V is applied across it causing power disspation P 1. Which one of the following is the correct relationship between P and P1?
A copper wire of radius r and length l has a resistance of R. A second copper wire with radius 2r and length l is taken and the two wires are joined in a parallel combination. The resultant resistance of the parallel combination of the two wires will be:
A) R/5
B) 5R/4
C) R/2
D) 4R/5