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Two unbiased dice marked from 1 to 6 are tossed together. The probability of the sum of the outcomes to be 7 in a single throw is
Explanation
When two unbiased dice are tossed simultaneously, the total number of possible outcomes in the sample space is 6 × 6 = 36. Each die has six faces (1, 2, 3, 4, 5, 6), and the outcomes are independent.
We need to find the probability that the sum of the outcomes is 7. The favorable outcomes (pairs) that result in a sum of 7 are:
- (1, 6)
- (2, 5)
- (3, 4)
- (4, 3)
- (5, 2)
- (6, 1)
There are exactly 6 such favorable outcomes. The probability (P) is calculated using the formula:
P = (Number of favorable outcomes) ÷ (Total number of possible outcomes)
P = 6/36 = 1/6
Thus, the probability of the sum of the outcomes being 7 is 1/6, which corresponds to option A.
SIMILAR QUESTIONS
Three dice, whose all six faces arc- marked ‘1’ to ‘6’, are thrown. The number of ways of getting a sum of 16 is
Three dice (each having six faces with each face having one number from 1 to 6) are rolled. What is the number of possible outcomes such that at least one dice shows the number 2?
A fair coin is tossed three times and the outcomes are noted. What is the probability of getting exactly two heads?
When three coins are tossed together, the probability that all coins have the same face up is:
A) 1/3
B) 1/6
C) 1/4
D) 1/8