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How many moles of water would be produced by the complete combustion of one mole of natural gas, CH4, in excess of oxygen ?
Explanation
The complete combustion of methane (CH4), which is the primary component of natural gas, is represented by the following balanced chemical equation:
CH4 + 2O2 → CO2 + 2H2O
According to the stoichiometry of this reaction, 1 mole of methane reacts with 2 moles of oxygen (O2) to yield 1 mole of carbon dioxide (CO2) and 2 moles of water (H2O). Therefore, the complete combustion of one mole of natural gas produces exactly 2 moles of water.
SIMILAR QUESTIONS
The number of moles of oxygen gas used in the complete combustion of 1 mole of glucose is :
One mole of hydrogen gas burns in excess of oxygen to give 290 kJ of heat. What is the amount of heat produced when 4g of hydrogen gas is burnt under the same conditions ?
How many moles of CO can be obtained by reacting 2.0 mole of CH₄ with 2.0 mole of O₂ according to the equation given below?
CH₄(g) + 1/2 O₂ → CO + 2H₂
The mass of 0.5 mole of N2 gas is
A tablespoon holds 0.5 mole of water. What is the number of molecules present in it?