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A person travels from his house to his office in 30 minutes but he takes 45 minutes to travel from his office to house via the same route. What is the ratio of the average velocity while going and the average velocity while returning ?
Explanation
Average velocity is defined as the total displacement divided by the total time taken. Since the person travels via the same route, the distance (and the magnitude of displacement) d remains constant for both trips.
Let v1 be the average velocity while going and v2 be the average velocity while returning.
- Time taken while going (t1) = 30 minutes
- Time taken while returning (t2) = 45 minutes
The average velocities are:
v1 = d / 30
v2 = d / 45
The ratio v1 / v2 is calculated as:
(d / 30) ÷ (d / 45) = 45 / 30 = 3 / 2
Therefore, the ratio of the average velocity while going to the average velocity while returning is 3/2.