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Q2
(CISF/2020)
Science & Technology › Basic Science (Physics, Chemistry, Biology)
Suppose m = HCF of x and y and n = LCM of x and y. Consider the following :
1. m2n ≤x2y
2. mn2 ≤x2y
Which of the following is/are correct ?
Result
Your answer:
—
·
Correct:
A
Explanation
The relationship between two numbers (x, y) and their HCF (m) and LCM (n) is defined by the fundamental property: x × y = m × n.
- Statement 1: m2n ≤ x2y. We can rewrite this as m(mn) ≤ x(xy). Substituting mn = xy, we get m(xy) ≤ x(xy). Dividing both sides by xy (assuming x, y > 0), we get m ≤ x. Since the HCF of two numbers is always less than or equal to the numbers themselves, this statement is correct.
- Statement 2: mn2 ≤ x2y. We can rewrite this as (mn)n ≤ x(xy). Substituting mn = xy, we get (xy)n ≤ x(xy), which simplifies to n ≤ x. This is incorrect because the LCM (n) is always greater than or equal to the numbers (n ≥ x and n ≥ y).
Thus, only statement 1 is correct.
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