A climber tries to reach the top of an object which is 130 m high. He can climb one metre per minute. However, as soon as he completes 5 metres, he slips down by one metre. The climber will reach the top in :

To solve this, we calculate the net progress of the climber in each cycle:

• Climbing rate: 1 metre per minute.
• Cycle: The climber climbs 5 metres (taking 5 minutes) and then immediately slips down 1 metre.
• Net progress per cycle: 5m - 1m = 4 metres.
• Time per cycle: 5 minutes (since the slip happens "as soon as" the 5m climb is completed).

We need to reach 130 metres. Let's calculate the progress after 31 full cycles:

• Distance: 31 cycles × 4m/cycle = 124 metres.
• Time: 31 cycles × 5 min/cycle = 155 minutes.

After 155 minutes, the climber is at 124m. Now, let's look at the next steps:

1. In the next 5 minutes (32nd cycle climb), he reaches 124 + 5 = 129 metres.
2. As soon as he completes these 5 metres (at the 160-minute mark), he slips 1 metre down to 128 metres.
3. He now needs to cover the remaining 130 - 128 = 2 metres.
4. At a rate of 1m/min, he takes 2 minutes to climb these 2 metres.

Total time: 160 minutes + 2 minutes = 162 minutes.
Conversion: 162 minutes = 2 hours 42 minutes.