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Q30
(CISF/2026)
Miscellaneous & General Knowledge › Important Days, Places & Events
If 31st December of a non-leap year is Sunday, then which one of the following days in that year occurs 53 times ?
Result
Your answer:
—
·
Correct:
B
Explanation
A non-leap year consists of 365 days. To find the number of weeks, we divide 365 by 7, which equals 52 weeks and 1 remainder day (365 = 52 × 7 + 1).
- In any year, every day of the week occurs at least 52 times.
- The single remainder day in a non-leap year results in one specific day occurring 53 times.
- Mathematical logic dictates that in a non-leap year, the first day (January 1st) and the last day (December 31st) of the year are always the same day of the week.
Since the question specifies that 31st December is a Sunday, it follows that 1st January was also a Sunday. This specific day is the "extra" day beyond the 52 full weeks. Therefore, Sunday is the day that occurs 53 times in that year. Options A, C, and D occur only 52 times.
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