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Q29
(CISF/2026)
Miscellaneous & General Knowledge › Important Days, Places & Events
In a class of 50 students, 20 students play cricket, 15 students play football and 10 students play both cricket and football. How many students play neither cricket nor football ?
Result
Your answer:
—
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Correct:
D
Explanation
This problem can be solved using the principle of set theory and Venn diagrams. Let C be the set of students who play cricket and F be the set of students who play football.
- Total number of students (Universal set, n(U)) = 50
- Students playing cricket, n(C) = 20
- Students playing football, n(F) = 15
- Students playing both, n(C ∩ F) = 10
First, calculate the number of students who play at least one of the two games using the formula: n(C ∪ F) = n(C) + n(F) - n(C ∩ F).
n(C ∪ F) = 20 + 15 - 10 = 25.
The number of students who play neither cricket nor football is the total number of students minus those who play at least one game: 50 - 25 = 25.
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