The number of moles of oxygen gas used in the complete combustion of 1 mole of glucose is :

The complete combustion of glucose (C6H12O6) is a chemical process where glucose reacts with oxygen to produce carbon dioxide and water. To determine the number of moles of oxygen required, one must balance the chemical equation: C6H12O6 + 6O2 → 6CO2 + 6H2O. In this reaction, glucose contains 6 carbon atoms, which require 6 molecules of CO2 to be formed, and 12 hydrogen atoms, which require 6 molecules of H2O. Counting the oxygen atoms on the product side gives a total of 18 (12 from CO2 and 6 from H2O). Since the glucose molecule itself provides 6 oxygen atoms, the remaining 12 oxygen atoms must come from 6 moles of diatomic oxygen gas (O2). Therefore, exactly 6 moles of oxygen are used for the complete combustion of 1 mole of glucose.