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Q5
(CISF/2023)
Miscellaneous & General Knowledge › Important Days, Places & Events
A, B and C alone can finish a job in 20, 25 and 30 days, respectively. A and B together start doing the job. However, they leave it after 10 days. The remaining part of the job is finished by C alone. How many days did C take to finish the job ?
Explanation
To solve this, we first determine the total work by calculating the Least Common Multiple (LCM) of the time taken by A, B, and C.
Total work = LCM(20, 25, 30) = 300 units.
- Efficiency of A = 300 / 20 = 15 units/day
- Efficiency of B = 300 / 25 = 12 units/day
- Efficiency of C = 300 / 30 = 10 units/day
A and B work together for 10 days:
Combined efficiency of (A + B) = 15 + 12 = 27 units/day.
Work completed in 10 days = 27 × 10 = 270 units.
Remaining work = Total work - Completed work = 300 - 270 = 30 units.
Time taken by C to finish the remaining work = Remaining work / Efficiency of C = 30 / 10 = 3 days.
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