The age of a man is three times the sum of the ages of his two sons. Five years hence, his age will be doubled of the sum of the ages of his sons. The fathers present age is

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Q: 63 (IAS/2002)
The age of a man is three times the sum of the ages of his two sons. Five years hence, his age will be doubled of the sum of the ages of his sons. The father’s present age is

question_subject: 

Maths

question_exam: 

IAS

stats: 

0,14,6,0,14,4,2

keywords: 

{'ages': [0, 0, 3, 2], 'age': [2, 1, 1, 2], 'present age': [0, 0, 3, 1], 'years': [1, 0, 0, 2], 'times': [5, 2, 7, 3], 'father': [15, 3, 10, 14], 'sons': [0, 1, 1, 1]}

Let`s assume the present age of the father is F years, and the ages of his two sons are S1 and S2 years, respectively.

According to the given information:

"The age of a man is three times the sum of the ages of his two sons."

This can be expressed as F = 3 * (S1 + S2).

"Five years hence, his age will be doubled the sum of the ages of his sons."

This can be expressed as (F + 5) = 2 * (S1 + 5 + S2 + 5).

We can simplify the second equation to (F + 5) = 2 * (S1 + S2 + 10).

Now, let`s solve the equations to find the value of F:

From the first equation, we have F = 3 * (S1 + S2).

Substituting this value in the second equation, we get:

3 * (S1 + S2) + 5 = 2 * (S1 + S2 + 10).

Simplifying further, we have:

3 * S1 + 3 * S2 + 5 = 2 * S1 + 2 * S2 + 20.

Combining like terms, we get:

S1 + S2 = 15.

Now, let`s try different values of S1 and S2 that satisfy the equation S1 + S2 = 15:

If we assume S1 = 5 and S2 = 10, we can check if it satisfies the equation.

5 + 10 = 15, which is true.

Therefore, the ages of the two sons are 5 and 10 years, respectively.

Now, let`s find the age of the father:

F = 3 * (S1 + S2) = 3 * (5 + 10) = 3 * 15 = 45.

So, the father`s present age is 45 years.

Therefore, the correct answer is 45 years.

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