A body is lifted by a man to a height of 1 metre in 30 seconds. Another man lifts the same body to the same height in 60 seconds. The work done by them respectively are in the ratio of

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Q: 90 (CDS-I/2003)
A body is lifted by a man to a height of 1 metre in 30 seconds. Another man lifts the same body to the same height in 60 seconds. The work done by them respectively are in the ratio of

question_subject: 

Maths

question_exam: 

CDS-I

stats: 

0,3,10,3,6,4,0

keywords: 

{'height': [0, 0, 1, 2], 'same height': [0, 0, 2, 1], 'seconds': [3, 3, 8, 6], 'ratio': [1, 0, 1, 12], 'metre': [0, 3, 4, 3], 'body': [27, 3, 23, 37], 'work': [1, 1, 10, 7], 'same body': [0, 0, 1, 0]}

The correct answer is option 1: 1:2. This means that the work done by the first man is in the ratio of 1 to the work done by the second man, and the work done by the first man is twice as much as the work done by the second man.

To understand why this is the correct answer, let`s first understand the concept of work. Work is defined as the force applied to an object multiplied by the distance the object is moved in the direction of the force. In this case, the force is provided by the two men and the distance is 1 metre.

The amount of work done by each man can be calculated using the formula: work = force × distance.

In the first scenario, the first man lifts the body to a height of 1 metre in 30 seconds. Since the force and distance are the same for both men, the work done by the first man is 1 × 1 = 1.

In the second scenario, the second man lifts the same body to the same height of 1 metre, but it takes him 60 seconds. So, the work done by the second man is 1 × 1 = 1.

Therefore, the work done by the first man is 1

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