To determine the maximum number of bulbs that can be safely connected in parallel in the circuit, we need to consider the power rating and the current rating of the circuit.

Given that each bulb has a power rating of 100W and the circuit has a fuse with a rating of 5A, we can use the formula P = IV, where P is the power, I is the current, and V is the voltage.

Since the voltage is given as 220V, we can rearrange the formula to solve for the current: I = P/V.

For each bulb, the current can be calculated as follows:

I = 100W / 220V

I ≈ 0.45A

To determine the maximum number of bulbs, we need to divide the maximum current rating of the circuit (5A) by the current rating of each bulb (0.45A):

5A / 0.45A ≈ 11 bulbs

Therefore, the maximum number of 100W-220V bulbs that can be safely connected in parallel in the circuit is 11.

Therefore, the correct answer is option 3.