A club has 108 members. Two-thirds of them are men and the rest are women. All members are married except for 9 women members. How many married women are there in the club ?

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Q: 145 (IAS/2000)
A club has 108 members. Two-thirds of them are men and the rest are women. All members are married except for 9 women members. How many married women are there in the club ?

question_subject: 

Maths

question_exam: 

IAS

stats: 

0,23,9,3,4,23,2

keywords: 

{'women members': [0, 1, 0, 0], 'many married women': [0, 1, 0, 0], 'club': [0, 2, 1, 1], 'members': [37, 11, 44, 71], 'women': [9, 8, 22, 46], 'men': [4, 3, 12, 9], 'thirds': [0, 1, 1, 2]}

Let`s solve the problem step by step:

1. Total number of members in the club = 108.

2. Two-thirds of the members are men, so the number of men = (2/3) * 108 = 72.

3. The remaining members are women. So the number of women = 108 - 72 = 36.

4. All members are married except for 9 women. So the number of married women = Total number of women - Number of unmarried women = 36 - 9 = 27.

Therefore, there are 27 married women in the club.

Hence, the correct answer is 27, which aligns with option (c).

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