In the electrical circuit (ABC) as shown in the figure given below, the resistances R1, R2 and R3 are same and equal to 30 ohm .If a source of voltage 2V is connected across one arm, the current drawn from the voltage source is

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Q: 58 (CDS-I/2002)
In the electrical circuit (ABC) as shown in the figure given below, the resistances R1, R2 and R3 are same and equal to 30 ohm .If a source of voltage 2V is connected across one arm, the current drawn from the voltage source is

question_subject: 

Maths

question_exam: 

CDS-I

stats: 

0,5,12,5,5,6,1

keywords: 

{'resistances r1': [0, 0, 1, 0], 'electrical circuit': [0, 0, 0, 2], 'voltage source': [0, 0, 1, 0], 'current': [0, 0, 0, 3], 'voltage 2v': [0, 0, 1, 0], 'arm': [2, 0, 1, 5], 'r2': [0, 0, 1, 3], 'r3': [0, 0, 1, 1]}

In the given circuit, we have a source of voltage connected across one arm of the circuit with resistances R1, R2, and R3, all equal to 30 ohms.

To determine the current drawn from the voltage source, we can use Ohm`s Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) across the circuit divided by the total resistance (R) of the circuit.

In this case, the voltage across the circuit is given as 2V. We need to find the total resistance of the circuit.

Since the resistances R1, R2, and R3 are all equal and connected in parallel, we can use the formula for the total resistance of parallel resistances:

1/R_total = 1/R1 + 1/R2 + 1/R3

Substituting the given resistance value of 30 ohms for each resistor, we get:

1/R_total = 1/30 + 1/30 + 1/30

= 3/30

= 1/10

Taking the reciprocal of both sides, we find:

R_total = 10 ohms

Now, we can use Ohm`s Law to calculate the current

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