The following figure shows displacement versus time curve for a particle executing simple harmonic motion : Which one of the following statements is correct ?

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Q: 34 (NDA-I/2017)
The following figure shows displacement versus time curve for a particle executing simple harmonic motion :
Which one of the following statements is correct ?

question_subject: 

Science

question_exam: 

NDA-I

stats: 

0,2,6,3,3,2,0

keywords: 

{'simple harmonic motion': [0, 0, 4, 4], 'time curve': [0, 0, 0, 1], 'displacement': [0, 1, 0, 3], 'phase': [0, 0, 3, 3], 'particle': [0, 2, 8, 30], 'following figure': [0, 3, 2, 4]}

Option 1: The phase of the oscillating particle is the same at t = 1 s and t = 3 s. This is incorrect because the displacement versus time curve does not show any specific time values. The x-axis of the graph represents time, but there are no labels or values provided.

Option 2: The phase of the oscillating particle is the same at t = 2 s and t = 8 s. Again, this is incorrect because we cannot determine the specific time values from the graph.

Option 3: The phase of the oscillating particle is the same at t = 3 s and t = 7 s. This is the correct answer. The graph shows that the displacement of the particle reaches a particular point (e.g., maximum or minimum) at both t = 3 s and t = 7 s. This indicates that the phase, or position of the particle in its cycle, is the same at both time points.

Option 4: The phase of the oscillating particle is the same at t = 4 s and t = 10 s. Similar to the other options, this is incorrect because specific time values cannot be determined from the graph.

In conclusion, option 3 is correct because the graph indicates

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