The length of a rectangle is increased by 60%. By what per cent would the width have to be decreased to maintain the same area ?

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Q: 78 (CAPF/2017)
The length of a rectangle is increased by 60%. By what per cent would the width have to be decreased to maintain the same area ?

question_subject: 

Maths

question_exam: 

CAPF

stats: 

0,9,5,9,3,0,2

keywords: 

{'rectangle': [0, 1, 0, 1], 'width': [0, 2, 1, 1], 'cent': [1, 2, 5, 5], 'length': [0, 0, 1, 0]}

To find the change in width of the rectangle, we need to understand the relationship between length, width, and area. The formula for the area of a rectangle is length multiplied by width (A = L * W).

Let`s assume the initial length of the rectangle is L, and the initial width is W. After increasing the length by 60%, the new length is L + (60% of L) = L + 0.6L = 1.6L.

To maintain the same area, the new width (let`s call it W`) can be calculated by dividing the initial area (L * W) by the new length (1.6L), resulting in W` = (L * W) / (1.6L) = W / 1.6.

The change in width can be calculated using the formula: Change in width = (Initial width - New width) / Initial width * 100%.

Substituting the values, the change in width = (W - W / 1.6) / W * 100% = (0.6W / 1.6) / W * 100% = 0.375 * 100% = 37.5%.

So, the correct answer

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